# Line slope calculator x+4y=27

**Straight line given by points A[3; 6] and B[7; 5]**

## Calculation:

**Slope-intercept form of line:**y = -0.25x+6.75

**Canonical form of the line equation:**x+4y-27 = 0

**Parametric form of the line equation:**

x = 4t+3

y = -t+6 ; t ∈ R

**Slope:**m = -0.25

**Slope angle of line: φ =**-14°2'10″ = -0.245 rad

**X intercept:**x

_{0}= 27

**Y intercept:**y

_{0}= q = 6.75

**Distance line from the origin:**d

_{0}= 6.5485

**The length of the segment AB: |AB| =**4.1231

**Vector: AB =**(4; -1)

**Normal vector: n =**(1; 4)

**Midpoint of the segment AB: M =**[5; 5.5]

**Perpendicular Bisector equation:**4x-y-14.5 = 0

**Vector OA = (3; 6) ; |OA| = 6.7082**

**Vector OB = (7; 5) ; |OB| = 8.6023**

**Scalar product OA .OB = 51**

**Angle ∠ AOB = 27°53'50″ = 0.4869 rad**